1 answer

How do you solve #(16+ \frac { 878} { 26} ) ^ { 3t } = 2#?

Question:

How do you solve #(16+ \frac { 878} { 26} ) ^ { 3t } = 2#?

Answers

#t=0.059131198#

Explanation:

#(16+878/26)^(3t)=2#

1) Using the law #lnm^n=nlnm#, take the natural log (ln) of both sides of the equation to prevent the variable from being an exponent.
#ln(16+878/26)^(3t)=ln(2)#
#(3t)ln(16+878/26)=ln(2)#

2) Isolate #t#.
#(3t)=ln(2)/ln(16+878/26)#
#t=ln(2)/ln(16+878/26)*1/3#

3) Solve using a calculator.
#t=0.059131198#

.

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