1 answer

How do you rationalize the observations that: #"a. ethyl alcohol is LESS volatile than ethylamine;"# #"b. ethyl alcohol is LESS

Question:

How do you rationalize the observations that: #"a. ethyl alcohol is LESS volatile than ethylamine;"# #"b. ethyl alcohol is LESS volatile than dimethyl ether;"# #"c. ethyl alcohol is LESS volatile than ethane."#?

Answers

Well funnily enuff, #"question a"# is the most debatable....

Explanation:

#a.# #"Ethyl alcohol is LESS volatile than ethylamine."#

#b.# #"Ethyl alcohol is LESS volatile than dimethyl ether."#

#c.# #"Ethyl alcohol is LESS volatile than ethane."#

For #b.# and #c.#, the capacity of ethyl alcohol to hydrogen-bond, which constitutes a quite potent force of intermolecular interaction, can rationalize the involatility of the alcohol.

#"Ethyl alcohol"# is LESS volatile than #"ethylamine"#, in that the strength of hydrogen bonding, of intermolecular interaction, is reasonably weaker in that the #N-H# is less polar, less charge-separated than the #O-H# bond.

But a physical scientist should always argue on the basis of data, which we ain't got here. I list the normal boiling points of each substance (which the question should probably have supplied, and asked you to rationalize:)

#"Ethane,"# #-89# #""^@C#;

#"Dimethyl ether,"# #-24# #""^@C#;

#"Ethylamine,"# #+16# #""^@C#;

#"Ethyl alcohol,"# #+78.4# #""^@C#.

Are these data consistent with the degree of intermolecular force as argued?

.

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