1 answer

How do you prove #sinx + cosx = -1#?

Question:

How do you prove #sinx + cosx = -1#?

Answers

This can not be proven because it isn't true.

This is easy to see with a few test values of #x#

For example

#x=0 rarr sin(0)+cos(0) = 1 != -1#

#x=pi/4 rarr sin(pi/4)+cos(pi/4) = sqrt(2)#

.

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