1 answer

How do you find the derivative of #sin^2(x)#?

Question:

How do you find the derivative of #sin^2(x)#?

Answers

#y^'=2*sin x* cos x#

Explanation:

#y=a*b#

#y'=a'*b+b'*a#

#y=sin^2=sin x*sin x#

#d/(d x) sin x=cos x#

#y'=cos x*sin x+cos x*sin x#

#y^'=2*sin x* cos x#

.

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