## Answers

We know 1lbs= 4.45Nmassof the elevatorM= [2400lbs*4.45N/lbs ] / ga) the net force the wall of the elevator shaft exert onthe motor if the elevator starts from rest is due to the imbalancein teh mass that istied on either end of the ropeF = maF = {[2400lbs-1000lbs * 4.45N /lbs]/g}*(g+g/4)the wall of the elevator shaft exert on the motor if theelevator starts from rest andd goes downF = {[2400lbs-1000lbs * 4.45N /lbs]/g}*(g-g/4) ..

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