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HELP PLEASE

Question:

You are investigating an elevatoraccident which happened in a tall building.An elevator inthis building is attached to a strong cablewhich runs over apulley attached to a steel support in the roof.The other endof the cable is attached to a block of metal called a counterweightwhich hangsfreely.An electric motor on the side of theelevator drives the elevator up or down by exerting a force on theside of the elevator shaft.You suspect thatwhen theelevator was fully loaded, there was too large a force on themotor.A fully loaded elevator at maximum capacity weighs2400 lbs.The counter weightweighs 1000 lbs.Theelevator always starts from rest at its maximum acceleration of g/4wheter it is going up or down.(a) What force does the wallof theelevator shaft exert on the motor if the elevator startsfrom rest and goes up? (b) What force does the wall of the elevatorshaft exert on the motor if the elevatorstarts from rest andd goesdown?

Answers

We know 1lbs= 4.45Nmassof the elevatorM= [2400lbs*4.45N/lbs ] / ga) the net force the wall of the elevator shaft exert onthe motor if the elevator starts from rest is due to the imbalancein teh mass that istied on either end of the ropeF = maF = {[2400lbs-1000lbs * 4.45N /lbs]/g}*(g+g/4)the wall of the elevator shaft exert on the motor if theelevator starts from rest andd goes downF = {[2400lbs-1000lbs * 4.45N /lbs]/g}*(g-g/4) ..

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