## Answers

1 - 2 - Here Calu n Не те 3 тоод а ЗХ 12 x 3 Som :- ③ we have to find AB and BA, if A = r 4 -47 @ 5-3 i 4 7 1-5 L-2 -21 -3 - Here [A]ax, ( Here 3 vows and 2 column) [e], ( Here 2 rows and 3 Columns) Let [] mxm and [Jnxp then [a b]mxp matrix multiplication is possible when number of Columns in first matrix y equal to the number of rows in second matrix. a) [A]gxo' [email protected] Hence here AB is possible. A.B : [ 4 - 4 5 -3 4 -5 -5 1 -2 -2 L -3x2 -3 -1 J2x3 = r 48-3 +(-4)*(-5) -58-3 + 1x-5 1 - 2x-3 + (-2)*(-5) 4X1+(-4)*(-3) -5X1+1X-3 -2x1+(-2)+(-3) 4x4 + (-4)*(-0) | -5x4 + 1X-1 - 2x4 + (-2)*(-1) 4+12 16+4 -12 + 20 15 - 5 6 tlo -5 -2 -3 +6 20-1 -8 +2 3x3 AB : r 8 10 | 16 16 201 -8 -21 4 -6 J 3X3

6) [b],xo.

[n] 2 Hence BA is possible. BA = [-3 47 1 4 | -5 1-5 -3 -11 +2x3 1 -2 -4 | 1 -2 3x2 1-3 x4 + 1X-5 +4X-2 -3*-4 + 1x1 +47-2 -5*-4+(-3)* 1 + (-1*(-2) 5x4 +(-3)*(-5)+(-1)*(-2) -12-5-8 -20 +15+2 1 2+1 - 20-3+2 2x2 BA - [ -25 51 . -3 192x2 n (③ we have to use appropriak Compound interest formula to find the amount. $ 24000 incerpted at 5% annual interest for t Years Compounded. P = $ 24000 r= 5% Po a t = 4 years a) Annually A = P(! + moto) where n = number of times the interest i Compounded per year.

Here compounded annually :: m = 1 nt + 7 niloo

So for mula becomes A = 24000 (1 + ) - = 24000 (to say 24000 / = x lobby lesbian bon lazy 1oox_loo x Loox too 20 20 21 - te (2034 A = 29172.15 So Amount = $ 29172.15 b) Semiannually Here n=2 so formula becomes A = P(1+ ) comes at 2x4 yo = 2400 (12 = 24000 ( 1 + +) $ 240 * (**) A : 29241.67 Amount = $ 29241. 67 so

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