## Answers

Standard enthalpy of formation is the change of enthalpyduring the formation of 1 mole of substance from its constituent elements, with all substancesin their standard states. (a) N2 (g) 3 H2 (g) ----> 2 NH3 (g) Since 2 moles of NH3 are formed, so AH°rxn is not equal to heat of formation of product. (b) Na (s) Cl2 (I) Cl2 (I) is not standard state of chlorine, so AH°rxn is not equal to heat of formation of product NaCl (s) (c) This is not formation reaction (d) P (s, white) 2 H2 (g) Br2 () > PH4Br (I) In this 1 moles of PH4Br is forming from its constituent elements. So, AH°rxn is equal to heat of formation of product (e) O (g) is not standard state of chlorine, so AH°rxn is not equal to heat of formation of product Option D is the right answer.

The balanced equation is 4 NH3 (g)3 02 (g) ----- --> 2 N2 (g) 6 H20 (g) We know that PV nRT At constant T and P, V oc n Accordingto balanced equation, 4 moles of NH3 produces 2 moles of N2 That is 4 L of NH3 produces 2 L of N2 So, 2.50 L of NH3 would produce 2.50 L 2/4 1.25 L of N2 Volume of N2= 1.25 L Option C is the right answer.

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