1 answer

For full load operation of 60Hz, 380V, 4 pole 30kW induction motor, the speed is 1746rpm,...

Question:

For full load operation of 60Hz, 380V, 4 pole 30kW induction motor,
the speed is 1746rpm, input current 56.2A power factor 90%.
In no load operation, input current 17.3A, power factor 13.5%.
In full load operation, assume that the mechanical loss is 25% of the total loss and no other losses.

a) Iron loss load efficiency
b) Find a rotor copper loss under full load
c) Iron loss
d) Find a fixed automatic hand under full load
e) Find the proportion of stator loss, iron loss, rotor copper loss and machine loss in total losses.

answer -
a) 90.1%
b) 953W
c) 714W
d) 801W
e) 24.3%


Answers

Given f = 6oita P=4 line input voltage = 380V NE 1746 R.P.m. input current 56.2 A - cosp=0.9 At no load I. - 17.3 A cosde13:5& Rolf coppes loss = 0.03 x 30822.6773 1-0.03 - 953,2786w () ison loss no-load losses me charsical loss = 1537.177 - 822.6723

.

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