## Answers

Friction force F = 1020 NAngle between the two ropes θ = 21 degreesAngle between central line and rope φ = θ /2=10.5 degreesThe sled moves with constant speed.So, applied force of two players in central line ( Horizontal line) is equal to frictional force.Let the force applied byeach player be F 'F ' cos φ +F ' cos φ = F2F ' cos φ = FF ' = F / ( 2 cos φ )= 518.68 N.

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