Answers
Solution :
Given that,
a ) n = 7
Degrees of freedom = df = n - 1 = 7 - 1 = 6
At 95% confidence level the t is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
t /2,df = t0.025,6 = 2.447
The critical value = 2.447
b)n =12
Degrees of freedom = df = n - 1 = 12 - 1 = 11
At 98% confidence level the t is ,
= 1 - 98% = 1 - 0.98 = 0.02
/ 2 = 0.02 / 2 = 0.01
t /2,df = t0.01,11 =2.718
The critical value =2.718
c )n = 27
Degrees of freedom = df = n - 1 = 27 - 1 = 26
At 99% confidence level the t is ,
= 1 - 99% = 1 - 0.99 = 0.01
/ 2 = 0.01 / 2 = 0.005
t /2,df = t0.005,26=2.779
The critical value =2.779
d )n = 14
Degrees of freedom = df = n - 1 = 14 - 1 = 13
At 98% confidence level the t is ,
= 1 - 98% = 1 - 0.98 = 0.02
/ 2 = 0.02 / 2 = 0.01
t /2,df = t0.01,13 =2.650
The critical value =2.650
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