## Answers

Let y = 1/x'0 = x^-10 therefore we know that for y = x^n then d y/d x = n . x^n-1 therefore y = x^-10 d y/d x = -10 . x^-10 -1 for n = -10 d y/d x = -10 . x^-11 and d^2 y/d x^2 = d/d x (d y/d x) = d/d x(-10 . x^-11) but d/d x (c f (x)).

.
= c . d/ d x (f (x)) , c = constant therefore d^2 y/d x^2 = d/d x (-10 . x^-11) = -10 . d/ d x (x^-11)

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