Answers
a)P(5 )=0.05
b)
P(no less than 4) =0.1+0.05 =0.15
c)
P(0) =0.2
d)
P(X>=3) =0.2+0.1+0.05 =0.35
e)
| x | f(x) | xP(x) | x2P(x) |
| 0 | 0.2000 | 0.0000 | 0.0000 |
| 1 | 0.1500 | 0.1500 | 0.1500 |
| 2 | 0.3000 | 0.6000 | 1.2000 |
| 3 | 0.2000 | 0.6000 | 1.8000 |
| 4 | 0.1000 | 0.4000 | 1.6000 |
| 5 | 0.0500 | 0.2500 | 1.2500 |
| total | 2.0000 | 6.0000 | |
| E(x) =μ= | ΣxP(x) = | 2.0000 | |
| E(x2) = | Σx2P(x) = | 6.0000 | |
| Var(x)=σ2 = | E(x2)-(E(x))2= | 2.0000 | |
| std deviation= | σ= √σ2 = | 1.4142 |
μ=2
6)
σ=1.414
7)
P(takes more than 6 minutes) =P(at least 3 in line) =0.35
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