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Le mul? L8m. D B h = 55m Jane My = 60kg Tanzan - My Fly h Position 2 (onen Tarzan Jane Coues है ) here using the proportional to the triangle ů 7 8 = 2h BA ko and Ad L-h X*%* L so, the height from the ground of the Center of mass of the wine is nisi htles 2 So, the en at position 1, f t : Ko Noco, 3 2 Kine tkivine energy (strautid up = 0, Jane tu farean = might Malin - y energy Jane Ki Tangan - W7 + 2 2 2 2 2 2 the energy + 22, w,? + Reit at position U = Potantial Waz ZO ht Ei mign + mug Now, the ci mergy 2 Im. ( 2 ) 11 energy at 2 = mg (72 (ma?? (where. Wy is angular speed before is . bedo after the graly
An W2 3 134 rad/s " Angular speed of Jame before She him 1.34 rad/s grabs WB. is the wy him, 1 angular speed after the grops him (m & m.) is the mass of Jane (mgtm.) and Tanzone angular momentom is conserved. As tuere is no net frietion, the meet forsque is zero and and the
Ngoma / twag = (180 + 72x82) Way 3 L3 3 = 13 W3 1 2 + m +12 2 Key rm2 S Now I r. Wm وا L3 6PoB.2.0.66 = 0.66 grads 11 9088 can the angular speed after she grabs of roll Using the proportions, A OA and ABCD ܢ from figure H2 L-d کو e A D 42 Jane ay M 2. 3 Coonen Led Taman neach iez und maximo neight by energy conservation, int key = UATKA (my stoma) 90) + mely) the - (my town) Bd+ mvoldte)