# Example 6.3 from Textbook. ONLY CALCULATE THE ENTROPY As discussed in the class, derive the best...

###### Question:

Example 6.3 from Textbook. ONLY CALCULATE THE ENTROPY As discussed in the class, derive the best fit polynomial (preferably quadratic) equation to perform the integration. Don't use the area under the curve rule as used in the textbook to find the integral value. Compare your results with textbook answers.
Example 6.3: Calculate the enthalpy of saturated isobutane vapor at 360 K from the following information: (1) compressibility-factor for isobutane vapor; (2) the vapor preschire of isobutane at 360 K is 15.41 bar; (3) at 300K and 1 bar, HS =18115J/mol (4) the ideal-gas heat capacity of isobutane vapor: C/R=1.7765+33.037x10-T Table 6.1: Compressibility Factors Z for Isobutane Plbar 0.10 0.50 2 4 6 8 340 K 350 K 360 K 370 K 380K 0.99700 0.99719 0.99737 0.99753 0.99767 0.98745 0.9883 0.98907 0.98977 0.99040 0.95895 0.96206 0.96483 0.96730 0.96953 0.92422 0.93069 0.93635 0.94132 0.94574 0.88742 0.89816 0.90734 0.91529 0.92223 0.84575 0.86218 0.87586 0.88745 0.89743 0.79659 0.82117 0.84077 0.85695 0.87061 0.77310 0.80103 0.82315 0.84134 0.75506 0.78531 0.80923 0.71727 10 12 - 15.41 ----
Table 6.2: Values of the Integrands Required in Ex. 6.3 Values in parentheses are by extrapolation. P/har [cazat)p/P] x 10€/-bar-! 0 (1.780) 0.10 1.700 0.50 1.514 2 1.293 1.290 1.395 8 1.560 10 1.777 12 2.073 14 2.432 15.41 (2.720) 1-(Z - 1)/PJ x 10 bar (2.590) 2.470 2.186 1.759 1.591 1.544 1.552 1.592 1.658 1.750 (1.833)
P2-P1 (intg1+intg2)/2 Area for each block P(bar) 0 0.1 0.5 0.1 0.4 1.5 2 Integral 1.78 1.7 1.514 1.293 1.29 1.395 1.56 1.777 2.073 2.432 2.72 2 4 6 8 10 12 14 15.41 1.74 1.607 1.4035 1.2915 1.3425 1.4775 1.6685 1.925 2.2525 2.576 0.17 0.64 2.11 2.58 2.69 2.96 3.34 3.85 4.51 3.63 2 2 2 2 1.41 26.47 Total Area under curve =

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