Answers
sin(x2+y2)dA where R is the region 
:
substitute x=rcosθ and y=rsinθ and convert dA to polar which is done by substituting dA with r*dr*dθ.
sin(r2sin2θ+r2cos2θ)rdrdθ ------> sin2θ+cos2θ=1
sosin(r2)r dr dθ.θ is between 0 and 2π, r is between 2 and 9
this iterated integral can be done by splitting it into 2 integrals and then multiplying them together
X 
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