1 answer

Confidence Interval Problem 18 Confidence Intervals: Problem 18 Previous Problem Problem List Next Problem (1 point)...

Question:

Confidence Interval Problem 18

Confidence Intervals: Problem 18 Previous Problem Problem List Next Problem (1 point) Chuck wants to determine a 98% confiden

Confidence Intervals: Problem 18 Previous Problem Problem List Next Problem (1 point) Chuck wants to determine a 98% confidence interval for the true proportion of times he rolls a 5 (using a fair, 6-sided die). How many rolls must Chuck make to get a margin of error less than or equal to .05? Chuck assumes that pis 1/6. n =

Answers

Solution :

Given that,

\hat p = 1/6=0.167

1 - \hat p = 1 - 0.167 = 0.833

margin of error = E = = 0.05

At 98% confidence level the z is,

Z\alpha/2 = 2.326 ( Using z table  

Sample size = n = (Z\alpha/2 / E)2 * \hat p * (1 - \hat p )

= (2.326 / 0.05)2 * 0.167* 0.833

=301.05

Sample size = 301

.

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