## Answers

Answer) Mass 04 Substance Acme) = 6.019 Initial Temperature (Ti) = 28.8 °C Final Temperature (74)= 46.5 °C specitic heat capacity CGA) ? Hoe Mass of substance B (ma) = 26.2g Initial Temperature (Tk) = 52.8°C Final Temperature CTA) = 46.5 °C Specific heat Capacity 04 B = 1.17 Fauc Heat flow from higher temperature to lower temperature quost = - m2 x CR x CTF - Tk) I gain = my x CA X CIG- T°) when two substance comes in contact quost = again. -max C₂ x C T - Tk) = mix CA X CTI - Ti) – 26.2 9 x 1.19 610)*(46.5 - 52.89% = 6.01G) CAX (46.5-20.8) °c - 30.654 x6 6.3) (J) = 6.01 x 25.4 x CA goc 193.12 J - 154.46 x CA gºc : A = 193.120 Igor A = 1.25 goc CA = 193.12 154.46 .. Specific heat of compound A = 1.25Tgie

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