Can someone help me solve 1 and 2?Answers
| x | P(x) | xP(x) | x2P(x) |
| 0 | 0.0323 | 0.0000 | 0.0000 |
| 9 | 0.0048 | 0.0435 | 0.3919 |
| 74 | 0.0006 | 0.0477 | 3.5329 |
| 304 | 0.0002 | 0.0490 | 14.9058 |
| 1279 | 0.0001 | 0.0825 | 105.5381 |
| 2699 | 0.0000 | 0.0871 | 234.9871 |
| -1 | 0.9620 | -0.9620 | 0.9620 |
| total | -0.6521 | 360.3179 | |
| E(x) =μ= | ΣxP(x) = | -0.6521 | |
| E(x2) = | Σx2P(x) = | 360.3179 | |
| Var(x)=σ2 = | E(x2)-(E(x))2= | 359.8927 | |
| std deviation= | σ= √σ2 = | 18.9708 |
1)
expected profit = -0.6521
2)
standard deviation =18.9708
3)
here this is binomial distribution with parameter n=11 and p=1/5
| probability = | P(3<=X<=6)= | ∑x=x1x2 (nCx)px(1−p)(n-x) = | 0.3806 | |
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