Answers
total volume = 65 + 75 = 140 ml = 0.14 L
concentration of NaHCO3 = 0.19 x 65 / 140 = 0.088 M
concentration of Na2CO3 = 0.17 x 75 / 140 = 0.091M
now mixture of NaHCO3 and Na2CO3 act as acidic buffer.
for acidic buffer
pH = pKa + log [Na2CO3] / [NaHCO3]
pKa of NaHCO3 = 10.3
pH = 10.3 + log[0.091] / [0.088]
pH = 10.31
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