Calculate the following. Show your work. Circle or place a box around your final answer. A...

Ans 1

The balanced reaction

2KClO3 (s) = 2KCl (s) + 3O2 (g)

Ans 2

Moles of KClO3 = 5*10^-2 mol

From the stoichiometry of the reaction

2 moles of KClO3 produces = 3 mol O2

5*10^-2 mol of KClO3 produces = 5*10^-2 * 3/2

= 0.075 mol O2

Mass of O2 produced = moles x molecular weight

= 0.075 mol x 32 g/mol

= 2.40 g

Volume of O2 = mass/density

= (2.40 g) / (1.428 g/mL)

= 1.68 mL

Ans 3

Volume of O2 = 42 mL

Mass of O2 = volume x density

= 42 mL x 1.428 g/mL

= 59.976 g

Moles of O2 = mass/molecular weight

= (59.976 g) / (32 g/mol)

= 1.874 mol

From the stoichiometry of the reaction

Moles of KClO3 reacted = 1.874 mol * 2/3

= 1.25 mol

Mass of KClO3 reacted = moles x molecular weight

= 1.25 mol x 122.55 g/mol

= 153.12 g

Ans 4

Mass of KClO3 = 55.2 g

Moles of KClO3 = mass/molecular weight

= (55.2g) / (122.55 g/mol)

= 0.450 mol

Moles of O2 formed = 0.450 mol x 3/2 = 0.676 mol

Mass of O2 formed = moles x molecular weight

= 0.676 mol x 32 g/mol

= 21.62 g

Volume of O2 = mass/density

= ( 21.62 g) / (1.428 g/mL)

= 15.14 mL