## Answers

Hope it helps you...pls do upvote

HNO (kq = 4.6*104) + tho HNO +HO HO 2 (aq) I 0.0322 MI H с – ч. 1TB 0.0322- 4 ka [no ] [ the ot] [UNG xon 4.68109 = x 0.0322-3 0.0322-X x? = Ź 173.913 0.0322-X -0.0322 20 x-tre - 2 173.913 After soling this quadastic ? 0.00362550 a 0.0322-X At equillium Scannell with CamScanner -0.0322 -0.00362550

ZE Enno 1 = 0.0285745 M x = 0.00362550 [NO, ] - M = 0,00362550 [Hoot 7 = x Now, pH = -log [hot] = -log (0,00362 pH = 2.47 0.02857 M [HNOL] = [MN027 0,028571 ra 1 = 0.00 3626 M cs Scanned with CamScanner

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