1 answer

Bookmarks People window Help GiF X + ..CO Question 6 of 14 Complete and balance the...

Question:


Bookmarks People window Help GiF X + ..CO Question 6 of 14 Complete and balance the following redox reaction in basic solutio
Bookmarks People window Help GiF X + ..CO Question 6 of 14 Complete and balance the following redox reaction in basic solution 103 "(aq) + Re(s) - Re0s (aq) + 10"(aq)| 04- 2 0+ 02 03 1 2 3 4 5 6 7 8 9 0 02 03 04 05 06 07 Do + ( -- (s) (1) (g) (aq) Re H30+ H e H2O OH H o - Reset . <H2O Delete 31 MacBook Air

Answers

IO3^-(aq) + Re(s) >>> ReO4^-(aq) + IO^-(aq)

Balance half reactions ;  

IO3^-(aq) >>> IO^-(aq)

balance the oxygen by adding H2O(l) and then balance hydrogens by adding H^+(aq) in opposite side ;

IO3^-(aq) + 4H^+(aq) >>>> IO^-(aq) + 2H2O(l)

balance charge by electrons (e^-) ;

IO3^-(aq) + 4H^+(aq) + 4e^- >>>> IO^-(aq) + 2H2O(l)

Above is balanced first half reaction.

Now second half ; Re(s) >>> ReO4^-(aq)

Similarly here , balance the oxygen and then hydrogen.

Re(s) + 4H2O(l) >>>> ReO4^-(aq) + 8H^+(aq)

balance charge by e^- ;

Re(s) + 4H2O(l) >>>> ReO4^-(aq) + 8H^+(aq) + 7e^-

Above is second half balanced equation.

Now in net ionic equation there should be no electrons , so multiply first half balanced with 7 and second half balanced with 4 to balance and cancel the electrons and then add up the multiplied equations as ;

7IO3^-(aq) + 28H^+(aq) + 16H2O(l) + 4Re(s) >>>> 7IO^-(aq) + 14H2O(l) + 4ReO4^-(aq) + 32H^+(aq)

Now remove the common H2O(l) and H^+(aq) from both sides to get balanced ionic equation of acidic medium as ;

7IO3^-(aq) + 2H2O(l) + 4Re(s) >>> 7IO^-(aq) + 4ReO4^-(aq) + 4H^+(aq)

As we have to balance the equation in basic medium then add equal number of OH^-(aq) on both sides as the number of H^+(aq) in above equation so that H^+(aq) + OH^-(aq) becomes H2O(l) and then you will remove common water (H2O) to get final balanced ionic equation in basic medium (having OH^-(aq) in equation) as ;

7IO3^-(aq) + 4Re(s) + 4OH^-(aq) >>> 7IO^-(aq) + 4ReO4^-(aq) + 2H2O(l)

Above is your required equation.

.

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