1 answer

Birthaay Paradox: Take 2 Homework. Unanswered At the end of June, a bunch of customers all...

Question:

Birthaay Paradox: Take 2 Homework. Unanswered At the end of June, a bunch of customers all having birthdays in July enter a b

Linear Congruential Generator Homework • Unanswered Which of the following criteria are necessary and sufficient for a Linear

Linear Congruential Generator: Example 2 Homework • Unanswered What is the period-length of the Linear Congruential Generator

Birthaay Paradox: Take 2 Homework. Unanswered At the end of June, a bunch of customers all having birthdays in July enter a bakery to order cakes for their July birthday celebrations. How many such customers must there be so that there is at least a 50% chance (>=.5 probability) that at least two of them were born on the same day in July (ignore the year). Assume that there are no other customers in the store and that there are no concerns about social distancing etc. Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a 5 b 7 с 9 d 11 e 13 f 15 g 17 h 19 .- 21 i 23
Linear Congruential Generator Homework • Unanswered Which of the following criteria are necessary and sufficient for a Linear Congruential Generator Xn+1 (aXn + b)modm- with non-zero b - to have a full period m (i.e. all m numbers in 0... m-1 are obtained before the cycle repeats itself)? n+1 = Multiple answers: Multiple answers are accepted for this question Select one or more answers and submit. For keyboard navigation... Show More a the greatest common divisor of a and is 1 b a-1 is divisible by 4 if m is divisible by 4 с a-1 is divisible by all prime factors of m d None of the above
Linear Congruential Generator: Example 2 Homework • Unanswered What is the period-length of the Linear Congruential Generator Xn+1 = (1Xn + 5)mod13 with seed Xo = 1? Numeric Answer: 0 Cannot be empty

Answers

Birthday Paradox:

The answer is b.7.

In the classic Birthday Paradon problem where the probability of two people having same birthday in a year is calculated, the probability for n people and 365 days comes out to be: 1- P(365,n)/365. In the given problem since the number of days is 31, it can be calculated by replacing 365 by 31. Hence the probability will be:

1- P(31,n)/31 Where P(n,r) denotes permutation.

When the value of n is 7 the probability is 0.518 which is the required answer.

Hope this helped. Please do upvote and if there are any queries please ask in comments section.

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