## Answers

* given p=0.65 n=32 eshng Birewal dist'butën P(x=>] = ng po ghar d) PCX=203 => 32420 60.65)1°C1-0-65358 3 0-1383 b) PCX>15) = 1-PCX315) =1-CP(x=0J+P(x=1) +..... +P(x=15)] - 1-2 3146653°(60-637......... sebe position ----+3143 065)*(1-0-6539 = 10:026896730732812 - 0.9731 5) PCX<14)= P(x=0) +P(x=1) 7.-.-- + P(x=137 2316060.65)°C106597 ...... .---- +324, bos%C-06875 -) 0.0041748348645432 Ĉ 0.0042 d) P(x>23) = P(x+24) +P(x=2537- --- -+P(x=32) 0.1584 iScan it wouldn't be unsual , since the probability is 0.1584 anned with CamScanner

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