1 answer

An object of mass 0.1 kg is attached to a spring of negligible mass and is...

Question:

An object of mass 0.1 kg is attached to a spring of negligible mass and is executing simple harmonic oscillation with an angular frequency of 3 rad/s. If vx(0) = +0.5 m/s and x(0) = −0.1 m, what is the phase φ? The general solution for such an oscillator is x(t) = A cos(ω t + φ).

10.0 points mass 0.1 kg is attached to a mass and is executing sim- 003 An object of spring of negligible ple harmonic oscill

10.0 points mass 0.1 kg is attached to a mass and is executing sim- 003 An object of spring of negligible ple harmonic oscillation with an quency of 3 rad/s. If v (0) what is the phase ? The general solution for such an oscillator is r(t) = A cos(wt ) angular fre- +0.5 m/s and x(0) -0.1 m, = _ 1. 1.03 2. 0.519 3. 2.112 4.0.9911 5. -3.112 6. Zero 7.3.142 8. 4.039 9. -1.039 10. -2.112

Answers

A Gs Cat) Nelecd5 () = -Aw Sin (0t+. at to, a (D) = -01 - 0.1 A Cos (0t) A Cos OI= ARain (0) 2 Sin (0+)e . O5= - A x 3 OS=

.

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