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The rate of current in LR circuit is, dI V-IR dt L The current is zero att 0 Then, dI V dt L 6.5 V 2.5 H =2.6 A/s The rate of increase of currentat the instant when the current is 0.550 A is, dl 6.5 V-(0.550 A)(7.70 Ω) dt 2.5 H = 0.906 A/s The current after the circuit is closed is, Rt (72029) 2.5 2.5 0.498 A After a long time the steady state current is, i(t)- 6.5 2.5 = 0.844 A
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