Answers
a. The cost of the equipment for the user is $125,000
Expected value of cost savings in:
1st year = 0.30 * 60,000 + 0.55 * 40,000 + 0.15 * 18,000 = $42,700
2nd year = $42,700 * (1+ 5%) = $44,235
3rd year = $44,235 * (1+ 5%) = $47,077
4th year = $47,077 * (1+ 5%) = $49,431
5th year = $49,431 * (1 + 5%) = 51,902
Therefore, E(PW) of the equipment = 42,700/(1 + 0.18) + 44,235/(1+ 0.18)2 + 47,077/(1+ 0.18)3 + 49,431/(1 + 0.18)4 + 51,902/(1 + 0.18)5= $145,222
since, E(PW) is greater than the cost to user, the new design is preferable to the current limit.
b.
the above diagram is the decision tree analysis of the above problem.
The above values for introduction of the new design are the expected cost savings in each case.
EVPI = EVUU - EVPP = $42,700 - $42,700 = 0
where, EVUU is expected value under uncertainity and EVPP is expected value under perfect prediction.
EVPI tells that value of the perfect information is zero.
Therefore, if we get perfect information at any cost above zero than we must refuse the offer.