An electron at point A in the figure has a speed v_g of 1.10 times 10...

Part A )

v = 1.1 X 10⁶ m/sec

m = 9.1 X10^-31 kg

q = 1.6 X 10^-19 C

d = 10 cm

r = d / 2 = 5 cm = 0.05 m

the equations are used is

F = m v² / r

and

F = q v B

then B = 9.1 X 10^-31 X 1.1 X 10⁶ / ( 1.6 X 10^-19 X 0.05 )

B = 1.251 X 10^-4 T

Part B )

using the right hand rule

here the the electron is having negative charge

then the direction of the magnetic field is into the page

Part C )

t = r / v

t = 3.14 X 0.05 / 1.1 X 10⁶

t = 1.427 X 10^-7 sec