## Answers

The balanced equation for the preparation of ammonium phosphate is

3NH_{3} + H_{3}PO_{4} ----> (NH_{4})_{3}PO_{4}

thus one mole of phosphoric acid produces one mole of ammonium phsophate

that is 98 g of phosphorica cid gives 149g of ammonium phosphate

Then 4.4 g gives = 4.4 x 149/98 = 6.689 g of ammonium phosphate

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