Answers
The balanced equation for the preparation of ammonium phosphate is
3NH3 + H3PO4 ----> (NH4)3PO4
thus one mole of phosphoric acid produces one mole of ammonium phsophate
that is 98 g of phosphorica cid gives 149g of ammonium phosphate
Then 4.4 g gives = 4.4 x 149/98 = 6.689 g of ammonium phosphate
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