# A worker stands a distance d = 0.325 m from the left end of a plank...

###### Question:

A worker stands a distance

d = 0.325 m

from the left end of a plank as shown in the figure. The plank is supported by three cords. Find the tension in each cord (in N). Assume the plank is uniform, with length L = 2.00 m and mass 29.5 kg, and the weight of the worker is 720 N. (Due to the nature of this problem, do not use rounded intermediate values in your calculations—including answers submitted in WebAssign.) A worker stands on a horizontal 2.00 m long plank a distance d from the left end. The plank is supported by three cords.

• A cord at the right end of the plank goes up and right, making a 40.0° angle with the horizontal and applying a force vector T1 on the plank outward along the cord.
• A cord at the left end of the plank goes vertically up, applying a force vector T2 on the plank outward along the cord.
• A cord at the left end of the plank goes horizontally left, applying a force vector T3 on the plank outward along the cord.

|T 1|

=
Write the torque equilibrium equation with the rotation axis about the left end of the plank. What are the forces acting in the vertical direction? You will need to write the correct component of T1.  N

|T 2|

= N

|T 3|

= N

(b)

What If? The worker now begins to walk to the right. If each of the cords can support a maximum tension of 780 N, which cord fails first?

cord 1cord 2     cord 3

At what location does this occur (measured in m from the left end of the plank)?

m

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