1 answer

A study by Allstate Insurance Co. finds that 82% of teenagers have used cell phones while...

Question:



A study by Allstate Insurance Co. finds that 82% of teenagers have used cell phones while driving (The Wal/Street Journal, May 5, 2010, Suppose a random sample of 100 teen drivers is taken. [You may find it useful to reference the z table.] a-1. Calculate the standard error for the sampling distribution of the sample proportion. (Do not round intermediate calculations. Round your answer to 4 decimal places.) Standard error a-2. Is the sampling distribution of the sample proportion approximately normal? O Yes No b. What is the probability that the sample proportion is less than 0.80? (Round value to 2 decimal places, and final answer to 4 decimal places.) Probability
c. What is the probability that the sample pr places, and final answer to 4 decimal places) oportion is within ± 0.02 of the population proportion? (Round z value to 2 decimal Probablity
A study by Allstate Insurance Co. finds that 82% of teenagers have used cell phones while driving (The Wal/Street Journal, May 5, 2010, Suppose a random sample of 100 teen drivers is taken. [You may find it useful to reference the z table.] a-1. Calculate the standard error for the sampling distribution of the sample proportion. (Do not round intermediate calculations. Round your answer to 4 decimal places.) Standard error a-2. Is the sampling distribution of the sample proportion approximately normal? O Yes No b. What is the probability that the sample proportion is less than 0.80? (Round "" value to 2 decimal places, and final answer to 4 decimal places.) Probability
c. What is the probability that the sample pr places, and final answer to 4 decimal places) oportion is within ± 0.02 of the population proportion? (Round "z" value to 2 decimal Probablity

Answers

Solution:

a-1: Calculate the standard error for the sampling distribution of the sample proportion.

Answer: The standard error is:

/ 0.82(1-0.82)-0.0384 -0.0384 (1-p) 100

a-2: Is the sampling distribution of the sample proportion approximately normal?

Answer: Yes

b. What is the probability that the sample proportion is less than 0.80?

Answer: The probability that the sample proportion is less than 0.80 is:

P (p < 0.80) = P (p-p , 0.80-0.82 SE 0.0384

  P-0.52)

Now using the standard normal table, we have:

Plþ < 0.80) P(s <-0.52) = 0.30 15

Therefore, the probability that the sample proportion is less than 0.80 is 0.3015   

c. What is the probability that the sample proportion is within small pm0.02 of the population proportion?

Answer:

0.80 0.82 p -p 0.84 0.82 P0.0384 P (0.80 < < 0.84) = 0.0384

=P(-0.52 <量<0.52 P P0.52 p-p = P 1-052 < SE

Pe<0.52)- P: <-0.52)

Now using the standard normal table we have:

P(0.80 < Þ < 0.84)-P(z < 0.52) _ P(z <-0.52) 0.6985-0.3015-0.3970

Therefore, the probability that the sample proportion is within small pm0.02 of the population proportion is 0.3970

.

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