1 answer

A spacecraft orbits the Earth unpowered in a circular path at a height of h =...

Question:

A spacecraft orbits the Earth unpowered in a circular path at a height of h = 365km above the Earths surface. At position A

A spacecraft orbits the Earth unpowered in a circular path at a height of h = 365km above the Earth's surface. At position A thrusters are applied briefly that DOUBLE the satellite's speed. RE = 6,380,000m; ME = 5.98E24kg; G = 6.673E-11N.m 2/kg 2; Earth (a) What is the period the spacecraft(in seconds) before the thrusters are applied? 5428 sec (b) What is the angular velocity of the craft at B (WB), where the radius has increased by 19percent from the circular orbit radius? Number Units

Answers

Sol Given RE = 6380000 m. ME = 5.98x1024k G = 6.673x10 Nm / kg A spacecraft orbit the earth ! height of h= 365 km = 65000 mspeed = 16.67X10 11 X 5.98x1024 of V (802 655.0) Booza 49693338.2 - 7049.3 m/s :. Angular Velocity w = 8 – 7049.3 8026550 2oo

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