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A reaction obeys the rate law: rate = k [A]2[B]. At some set of concentrations, the...

Question:

A reaction obeys the rate law: rate = k [A]2[B]. At some set of concentrations, the rate is found to be 8.2 x 10-2 M/sec. What will be the rate of reaction if the concentration of A is halved and the concentration of B is doubled? A. 4.1 x 10-2 M/sec B. 8.2 x 10-2 M/sec C. 5.0 x 10-1 M/sec D. 1.6 x 10-1 M/sec


Answers

Rate law : Rate =k[A]²[B] | Rate = .8.2x10² m/s = X [A]²[B] =R (het) Mrow concentration of A is halved so it becomes [A22] co

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