1 answer

A person rides a loop-the-loop, as shown, at an amusement park. The cart circles the track...

Question:

A person rides a loop-the-loop, as shown, at an amusement park. The cart circles the track at a constant speed. At the top of the loop, the normal force exerted by the seat is equal to the weight of the person. At the bottom of the loop, the person will experience

normal force equal to three times the weight of the person.

no force from the seat.

a normal force equal to two times the weight of the person.

a normal force equal to the weight of the person.

a normal force greater than the weight of the person, but it cannot be calculated from the information given.


Answers

At Top of Loop, Normal force mit my Now it is given that - Normal force = my mre=em g- 1) At bottom of the loop, Normal force

Normal force at the bottom is three times the weight of the person.

Please ask your doubts or queries in the comment section below.

Please kindly upvote if you are satisfied with the solution.

Thank you.

.

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