A person rides a loop-the-loop, as shown, at an amusement park. The cart circles the track at a constant speed. At the top of the loop, the normal force exerted by the seat is equal to the weight of the person. At the bottom of the loop, the person will experienceAnswers
Normal force at the bottom is three times the weight of the person.
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At Top of Loop, Normal force mit my Now it is given that - Normal force = my mre=em g- 1) At bottom of the loop, Normal force = mirting - Put value frouli) . ang mg=) 3 mg . Normal force is equal to thee times the ansight - of persoh.
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