# A parallel-plate capacitor has a plate area of A = 250 cm2 and a separation of...

###### Question:

1. A parallel-plate capacitor has a plate area of A = 250 cm2 and a separation of d = 2.00 mm. The capacitor is charged to a potential difference of V0 = 150 V by a battery. A dielectric sheet (κ = 3.50) of the same area but thickness = 1.00 mm is placed between the plates without disconnecting the battery. (See figure 24-18 on page 642).
1. Determine the initial capacitance of the air-filled capacitor.
2. Determine the charge on the each plate before the dielectric is inserted.
3. Determine the potential difference between the plates after the dielectric is added.
4. Determine the electric field in the space between each plate and the dielectric.
5. Determine the electric field in the dielectric.
6. Determine the free charge on the plates after the dielectric is added.
7. Determine the charge induced on each face of the dielectric after it is inserted.
8. Determine the capacitance after the dielectric is in place.

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