1 answer

A mixture of helium and neon gases at 335 K contains 3 times the number of...

Question:

A mixture of helium and neon gases at 335 K contains 3 times the number of helium atoms as neon atoms. The concentration (n/V

A mixture of helium and neon gases at 335 K contains 3 times the number of helium atoms as neon atoms. The concentration (n/V) of the mixture is found to be 0.150 mol/L. Assuming ideal behavior, what is the partial pressure of helium? kPa

Answers

1st calculate the total pressure

Use:

P*V = n*R*T

P = (n/V)*R*T

= 0.150*0.0821 * 335

= 4.126 atm

= 4.126*101.33 kPa

= 418.1 kPa

Mole fraction of He = 3/4

So,

Partial pressure of He = P * Mole fraction of He

= 418.1 *(3/4)

= 314 kPa

Answer: 314 kPa

.

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