Answers
1-23cm -0.23m - 24 c v=2 litres - 2X10-3 md T2 = 86°C 2 = 24X10- B = q X10-4 ,- & Area = Volume = 2x10-3 lengh 0.23 8.6956410-3m² volume of liquid overflows => AV = V(B-34DDT - (2 x 10-3) (9x10-4 - 3624x108) (62) - 1.026724444 - 1.026 72x10 cm (1.626 x 10 cm3] [102.6 cm 3) Vrenang = V - DV = (2x10 3 - = (1-897L 1.02672410-4)
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