Answers
When the string is in T1 = 200 N tension frequency be f1
Then
and
When the string is in T2 = 242 N tension frequency be f2
Add these 2 equations to obtain
and frequency is proportional to square root of tension
or
Therefore plug this in the previous equation
or
Therefore the frequency of the tuning fork is
answer is 126 Hz
- f1 = 6
2-f=6
12 - f1 = 12
f2/f1 = T2/T= 242/200 = 1.1
12 = 1.181
1.1f1-f1 = 12
f1 = 12/0.1 = 120 Hz
f = fi + 6 = 120 + 6 = 126 Hz
.
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