1 answer

A cord pulling a cart up along a frictionless plane inclined at angle theta = 15...

Question:

A cord pulling a cart up along a frictionless plan

A cord pulling a cart up along a frictionless plane inclined at angle theta = 15 degree. The box has mass m = 5.0 kg, and the force from the cord has magnitude T_1 = 25 N. What is the box's acceleration along the inclined plane? Calculate the normal force F_N exerted by the inclined plane towards the cart.

Answers

Since there is no friction, only two forces are acting along incline, one is tension which is pulling up the plane and component of gravitational force, pulling down the plane.

The component of gravitational force along incline is mg*sin(15)

Net force = T- mg*sin15o

Net force = 25 - 5*9.81*sin(15o)

Net force = 12.305 N up the plane

1) Acceleration = force/mass = 12.305/5

a = 2.46 m/s

2) Normal force is component of weight

N = mg*cos(15)

N = 47.38 Newtons

.

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