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The velocity of the salmon leaving the water in earth coordinates is the vector sum of 6.75 m/s (relative to water) and 1.65 m/s (relative to earth). The 6.75 m/s is a hypotenuse of a right triangle for which the upward velocity leg is
sqrt[(6.75)^2 - (1.65)^2] = 6.55 m/s
Set (1/2)M V^2 = M g H, with V = 6.55 m's, and solve for H.
The M's cancel..
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