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A chemist mixed some 15% peroxide solution ith some 6% peroxide solution to make 300 ML of a 9% peroxide solution. How many milliliters of the 15% solution was used? ---------- Follow the active ingredient. -------------- 15% solution DATA: Amt = x ML ; amt of active ingredient = 0.15x ML --------------- 6% solution DATA: Amt = "300-x"ML ; amt of active ingredient = 0.06(300-x)= 18-0.06x ML ---------------- 9% Mixture DATA: Amt = 300 ML; active = 0.09*300 = 27 ML EQUATION: active + active = active 0.15x + 18-0.06x = 27 0.09x = 9 x = 100 ML (amt of 15% solution needed in the mixture) ============ Cheers, Stan H..
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