Answers
given are
s1=44.2m
s2=29m
m=15kg
theta=40.8 degrees
x and y component of velocity is
vox=vcos(40.8)
Voy=vsin(40.8)
S1=voxt
44.2=vcos(40.8)t
T=44.2/vcos(40.3)
Y=voyt+1/2at^2
29=vsin(40.3)t+1/2(-9.8)t^2
29=vsin(40.3)t-4.9t^2
29=vsin(40.3)(44.2/vcos40.3)-4.9(44.2/vcos(40.3)^2
4.9*1953.6/v^2cos(40.3)=44.2tan(40.3)-29
12551.5/v^2=8.48
12551.5/8.48=v^2
V=38.4m/sec—answer
T=44.2/vcos(40.3)
=44.2/38.4cos(40.3)
T=1.5 sec
Using above equation
29=vsin(40.3)t-4.9t^2
29=38.4sin(40.3)t-4.9t^2
4.9t^2-38.4 sin(40.3)t+29=0
4.9t^2-24.8t+29=0
T1=3.22sec
T2=1.8sec
X=voycos(40.3)t
=38.4 cos (40.3)*1.8
x=52.7 m
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