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€90 A+B → 20 AH = -620.5K J, 45, = 335 JK! eq: € + D AH = 429kJ, AS, = -248 JK' The chemical equations are named as eg.
, and corresponding enthalpy changes y entropy changes are denoted Ah, as, and AH₂, A5, respectively .. so that they can easily sedisti be distinguishable We have to arrange the above two equations in such. a way so that we can reach to the final equation final eq. AtByze If we multifly eg: ① by 2 We get eq. 6.
90 20 ~ 2D, AH3 = 2 AH, & 452= 2952 Now, "If we substract eq. ③ from eq. we will 7 reach to the final eq. [eq. - eq.
] A+B-720 AH , Asia 2.0 - 20. AHz , ASZ A+B-20 d none or ATB 20 AH₂AH, - AH3. 2. AH= 45,-453 is AH.SAH, -2 0 Ha =-620.5 KJ -(X 429) KJ!
... AH = -147.8.5 kJ.
.
Again, Asa AS, - AS3 : AS, - (2x862) = 335 3k' – f2x(+248)}JK! = 335 + 496 jul = 831 JKT = 83! JK! . ?. 0.831 kJk' kz kilo. . .
K= Kelvin. Now, Gibb's free energy change at temperature T is given by. AG= 4H-TAS Here for this reaction, T= 298 Ki. :: AH = -1478.5 RJ,032.0.831 KJKT ::09-614785R3-298K* 0.831 RJ*') :5-17260138 kJ AG at 2.984 for the reactis is . (31726138 R JE
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