1 answer

6.–/10 pointsSerPSE10 22.3.P.010. Ask Your Teacher My Notes Question Part Points Submissions Used Three point charges...

Question:

6.–/10 pointsSerPSE10 22.3.P.010.

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My Notes

Question Part

Points

Submissions Used

Three point charges lie along a straight line as shown in the figure below, where q1 = 6.30 µC, q2 = 1.59 µC, and q3 = -2.12 µC. The separation distances are d1 = 3.00 cm and d2 = 2.00 cm. Calculate the magnitude and direction of the net electric force on each of the charges.

Three charges lie along a horizontal line. Positive charge q1 is on the left. Positive charge q2 is a distance d1 to the right of q1. Negative charge q3 is a distance d2 to the right of q2.

(a) q1

magnitude N

direction ---Select--- to the left to the right

(b) q2

magnitude N

direction ---Select--- to the right to the left

(c) q3

magnitude N

direction ---Select--- to the left to the right

7.–/10 pointsSerPSE10 22.3.P.012.

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My Notes

Question Part

Points

Submissions Used

Particle A of charge 3.06  10-4 C is at the origin, particle B of charge -6.60  10-4 C is at (4.00 m, 0), and particle C of charge 1.06  10-4 C is at (0, 3.00 m). We wish to find the net electric force on C.(a) What is the x component of the electric force exerted by A on C?
N

(b) What is the y component of the force exerted by A on C?
N

(c) Find the magnitude of the force exerted by B on C.
N

(d) Calculate the x component of the force exerted by B on C.
N

(e) Calculate the y component of the force exerted by B on C.
N

(f) Sum the two x components from parts (a) and (d) to obtain the resultant x component of the electric force acting on C.
N

(g) Similarly, find the y component of the resultant force vector acting on C.
N

(h) Find the magnitude and direction of the resultant electric force acting on C.

magnitude N

direction ° counterclockwise from the +x-axis


Answers

2, 8m 9im ←o-ㄧㄣ 3 k 2,9 Anu 0.032 6 02 反 2. kq 0 .0S 0.02. 3 티스 广. 2. 5

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