## Answers

for any doubt feel free to ask

given T 2517 dx } 2 r215 버 2rs제 so fW= 2기라4-30+제 국제s 2 쪄 25 제3 2274-30 라2세s + X +215 JI 2 (+2xIs) - 2(+25) + (2C+2) ㅗ (+27-5) ㅗ (2429) 2+ 2라5) 2 (2) 12. x-) =2+ㅆ 2t2 + | 2 + 1, (2x42) 늘 느 12. 2 (-3)(十) ( (2x+2) 24를 하서5 +(2× 1 (자-3) In tel [ - ㅋ f(x) = - t 24 \(x+2) 3 2 2. (+2X-S) (3) (x+S)

(2x+2) Nor= f fladdx = 2 (x²+2x+5) - 3 ( 4 ats): /2ext ļ ( 2742 J x 12.-15 oda-3 2x + 1 ln | x²+2x-151 + 2 ln (x-31 - 2 In 1x+51fc -da = ln I go to st du = ln(x-alte Answer ( 5 9'629 Hx2 2x-1 das b) Т x2 +16 2x-1 Let 2u x²46 2²16 x² +16 fro) Ix 2142 x² +16 4 4 Now du I= 22 x² +16 dx 4 s fre) dx = ( 2 = ln 1x27161 - 1 fant (x) +C I = ln 1x416 1 - 4 tant ( 2 ) + < Answer 4 =) li baada = = fani

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