1 answer

24. A radioisotope of argon, 35 Ar, lies below the "band of stability: (n/p ratio too...

Question:

24. A radioisotope of argon, 35 Ar, lies below the band of stability: (n/p ratio too low). One would predict that it decays

24. A radioisotope of argon, 35 Ar, lies below the "band of stability: (n/p ratio too low). One would predict that it decays via (a) positron emission (b) beta emission (c) neutron emission (d) alpha emission (e) fission

Answers

Hope it'll help. For further queries comment down below.

Answer::::::Positron emission

36Ar18 = Stable isotope

35Ar18 unstable isotope=radioisotope

n/p(17/18) for 35Ar18 is 0.94<1.

This indicated that it contains more protons than the neutrons(Mass number-Atomic number). It can undergo positron emission to increase number of neutrons by 1. So, The positron emission or beta decay will convert Ar-35 to Cl-35, stable isotope.

35Ar18 + -1e0---> 35Cl17 + 0v0

proton inside a nucleus is converted into a neutron and releases a positron and an electron neutrino. n/p ratio of produced 35-Cl is nearly 1.

Here is the information about other options as well,

Beta emission- Atomic number will increase by 1.

So number of neutrons will decrease and n/p will go even lower.

Neutron emission- Mass number Decreases by 1. Number of neutrons will decrease and n/p will be lower.

Alpha emission- Decreases atomic number by 2 and mass number by 4. So, Neutrons will be deccrease by 4. n/p will be lowered.

Fission- Decay of an atom into lighter nucleus.

.

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