![(16 points] Use the scale change and time delay theorems along with the appropriate transform pairs to find the Fourier trans](https://i.imgur.com/anN1mXf.png)
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![xalta () (1) 4+, 2 sinc(w) -. da (= T () , ze w sinc (w) M (4) = 2 sinc [2(t-1)] sincets - Tx T(-w) asinc (2+) E 21 = TT TT (](https://i.imgur.com/L0nvnX2.png)
xalta () (1) 4+, 2 sinc(w) -. da (= T () , ze w sinc (w) M (4) = 2 sinc [2(t-1)] sincets - Tx T(-w) asinc (2+) E 21 = TT TT (4) 2 sine [2(t-1)] Tenda TT (W/M) MCH 1[43] 1 Act) s 1/2) + sine (2/2) 8 sine (46) Xews sinc" (40) 7 CH = Sinc[(+-3)/4] sincets TxTT (-0) siněct) c (ox () * 1x 11(-2)] *24() - Itality) Since" (+2 ) W3 T 1 (2012)
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