## Answers

5- 30 uc het at point p o field is zero Fieldi diee to tlonc charge E = louc HTE x2 Field due to +300c charge 2рд с Era 40€, (5-x)? - As E, and Ē are in opposite direction - So for net electic field to be zero then 16,1 = 1E! louc Зодс 9719, 72 FTS. (5-xyz 1 / 2 = 5.22 (5-x)2 = 3x² 95 +x²10x = 3x? 2re? tox25 50 - 10+ stopt 200 = -10 I g 1013 x = -5 + 5 1.8.3 mm MAS

13 Force on election F = 4,92 - (1.6X10 19 ) Axico . &T&82 (1.592x11092 Fr 10:24 xó!? N F = a 1-024x 1616 N Attractive - force a strength of field at 1.50mm away from proton (los) 2x1012 7 47€ 8?- E = 6.48102 NYC = 640 N/c. Potential 6 Va ate q = 1.6X10719x9x109 1.sx 10-6.

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V= g.6x 10 4 Valk

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