## Answers

Moleular oumula d tuctose = CM2O6 = (C,0), Impewcal qoumala fucton CH20 quam oeach elements im Chg0 129 imele) o g (2mole) H 1male o 0 16 Empircical 12+2t16= 30 9 Mars mau /o C mas o elamant X loo Cempound X lo0 = 40 1. 30 Molar mau mam loo= 6.67. 30 /. may / 30 A/00= 53.33

(B o loog umkmeron cempound, 40 0 Myduogen69 mai Cauben mars 6.7 53-3 mars towest valur malos oCauben 3.33 umele 40 males otydun 67-6.mele 1 meles o O 53-3 3.33 mele 16 Ouvide uall value uuth the lowest value C = 3.33 H6.4 3.33 1 0:3.33 1 3.33 3.

33 C420 (MM30gel Empinical Youmula CM,0, for 5mele or 1 vmele its moleular mas = 900 am 900 ab molecular mam - 180 m=Moleuular Mas Empurial Mas Me6 3 0 Moleular oumula Empiuial umula)m = (CK,0)6 C&M1206

foumula i Na, P04 (c) NaE 699(3mole) Vmass 1 81a (tmole) 649 (4mele) Nag PO4= 16g P mau 0 mam Molecular man 69 $ mars 42.1. Na -X100 164 31 164 mam 1 64 -Xl00 = 39.0 1 0 D) per toog Cempound C = 34 34 0 22-84 H1.12 F-13. P moles o C 34.29 2.85 12 moler 0-22-8 16 1 43 moles o H= 319 719 moles a P 22-11 0.71 31 moles o F -13.56 -0.71 19 lowest valu Aivide au valu uth Lowest valus,

C:.95 4 0 1.43 0.7H H: 719- 10 P: 0.7H - 1 0 7H F 0.1 1 Empirical Foumula = CHIF2P 140 Cmpinial tormula meleular Weht 140gmet Max Molecular weight Empwial 4ormula mau 140 09 140 1 Molecular toumula = Cy1o FOP I!

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