Answers
a)
energy stored in sprinter E1 = (1/2)*k*x1^2
k = spring constant = 33 N/mm = 33*10^3 N/m
x1 = stretch in sprinter = 44 mm = 0.044 m
E1 = (1/2)*3*10^3*0.044^2 = 2.904 J
energy stored by rest E2 = (1/2)*k*x2^2
k = spring constant = 33 N/mm = 33*10^3 N/m
x2 = stretch in sprinter = 32 mm = 0.032 m
E2 = (1/2)*3*10^3*0.032^2 = 1.536 J
excess energy store by sprinter = E1 - E2 = 1.368 J
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b)
kinetic energy recovered = 97% of E1
KE = (97/100)*2.904 = 2.82 J
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c)
the missing energy goes in the form of internal energy
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